. A 8.6 g sample of iron(II) chloride (FeCl2) reacts with 16 g of HA in the presence of 6 g of NaOH to give 15.8 g of ir

[answerhappygod]

A 8 6 G Sample Of Iron Ii Chloride Fecl2 Reacts With 16 G Of Ha In The Presence Of 6 G Of Naoh To Give 15 8 G Of Ir 1 (49.32 KiB) Viewed 94 times

. A 8.6 g sample of iron(II) chloride (FeCl2) reacts with 16 g of HA in the presence of 6 g of NaOH to give 15.8 g of iron(III) complex [Fe(A)2Cl] with reference to the below chemical equation: FeCl2(aq) + 2HA(aq) + 2NaOH(aq) → Fe(A)2Cl(s) (Given: Molar mass of HA = 145.2 g/mol; Molar mass of Fe(A)2Cl = 379.6 g/mol) (a) The chemical reaction above can possibly be named as several reaction types. Name three of them. (3 marks) (b) Which reactant is the limiting reagent? Show your calculation. (5 marks) (c) Determine the % yield of the reaction. (2 marks)