- Consider The Following Reaction Pb4 Aq 2 Cut Aq Pb2 Aq 2 Cu Aq E 1 53 V The Nernst Equation At 25 1 (23.67 KiB) Viewed 57 times
Consider the following reaction. Pb4+ (aq) + 2 Cut (aq) Pb2+ (aq) + 2 Cu²+ (aq) E' = +1.53 V The Nernst equation at 25 °
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Consider the following reaction. Pb4+ (aq) + 2 Cut (aq) Pb2+ (aq) + 2 Cu²+ (aq) E' = +1.53 V The Nernst equation at 25 °
Consider the following reaction. Pb4+ (aq) + 2 Cut (aq) Pb2+ (aq) + 2 Cu²+ (aq) E' = +1.53 V The Nernst equation at 25 °C is 0.0592 E = E - Flog (O Calculate the cell potential, E. if [Pb4 +) and (Cut) equal 0.112 M, and (Pb2 +1 and (Cu²+1 equal 0.401 M. O 1.481 V O 1.432 v O 0.17 V O 1.579 V
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