- 10 10 And Cd2 Aq 2 E Cd 3 E 0 41v Cu Aq E Cu S E 0 52 V Ag Aq Ag S E 0 80 V Based 1 (29.37 KiB) Viewed 44 times
10. 10 and Cd2+ (aq) +2 e → Cd (3) E° = -0.41V -> Cu+ (aq) +e → Cu (S) E°= +0.52 V Ag+ (aq) + Ag (S) E° = +0.80 V Based
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
10. 10 and Cd2+ (aq) +2 e → Cd (3) E° = -0.41V -> Cu+ (aq) +e → Cu (S) E°= +0.52 V Ag+ (aq) + Ag (S) E° = +0.80 V Based
10. 10 and Cd2+ (aq) +2 e → Cd (3) E° = -0.41V -> Cu+ (aq) +e → Cu (S) E°= +0.52 V Ag+ (aq) + Ag (S) E° = +0.80 V Based on the electrode potentials given above, which of the following is the strongest reducing agent? Which one is most reactive metal? A. Cd (s) B. Cd2+ (aq) C. Cu (S) D. Ag (S) E. Agt (aq) 11. Calculate AG for each of the following reactions (Bonus): a) 4Ag (s) + O2(g) + 4H+ (aq) + 4Ag+ (aq) + 2H20 (1) b) 2Ag (s) + 12 O2(g) + 2H+ (aq) + 2Ag* (ag) + H2O (1)
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!