2. Hydroxide is a good base and a good nucleophile. If -OH acted as a base, it would remove the most acidic proton from
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2. Hydroxide is a good base and a good nucleophile. If -OH acted as a base, it would remove the most acidic proton from
2. Hydroxide is a good base and a good nucleophile. If -OH acted as a base, it would remove the most acidic proton from the reactant (it is called a proton transfer step). If it acted as a nucleophile it would attack the most electrophilic site (mostly a carbon with a positive or partial positive charge) (and it is called a nucleophilic attack step). Oops, I kinda answered the previous question here. Now, could you please draw the intermediates (product of the step-1) for the following reactions where hydroxide is acting as a base and a nucleophile? Give the structure of the immediate product of the step-1 NaOH as NaOH as a base a base & Br NaOH as a nucleophile NaOH as a nucleophile
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