R-0.008315 kJ/mol K F = 96.48 kJ/v•K 1. (10 pts) A cell must import Cufor proteins that are involved in oxidative phosph

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R-0.008315 kJ/mol K F = 96.48 kJ/v•K 1. (10 pts) A cell must import Cufor proteins that are involved in oxidative phosph

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R 0 008315 Kj Mol K F 96 48 Kj V K 1 10 Pts A Cell Must Import Cufor Proteins That Are Involved In Oxidative Phosph 1
R 0 008315 Kj Mol K F 96 48 Kj V K 1 10 Pts A Cell Must Import Cufor Proteins That Are Involved In Oxidative Phosph 1 (43.57 KiB) Viewed 55 times
CHEMISTRY NOT BIOLogy
R-0.008315 kJ/mol K F = 96.48 kJ/v•K 1. (10 pts) A cell must import Cufor proteins that are involved in oxidative phosphorylation. Consider a cell at 37 °C with a transmembrane potential of 70 mV (inside negative), where the Cui concentration outside the cell is 0.02 uM and 0.15 um inside the cell. a. Write the expression that is used to calculate the free energy of transport for charged solute b. Substitute the appropriate values from the situation described above to calculate the free energy of transport for Cu?* into the cell. You do NOT need to solve the equation. dhara c. Which term(s) in the expression for free energy of transport are energetically favorable in the situation described above? A bro bones The concentration term The electrochemical term Both terms Neither term
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