2 OF 1.3 HD OS 2 NA VAN 10 457 2 1.55 1.55 1.54 SI 251 251 1.50 1.50 SZI 1 1.21 1.19 0.52 OSO 0 0.56 en 450 400 -350 300

[answerhappygod]

2 Of 1 3 Hd Os 2 Na Van 10 457 2 1 55 1 55 1 54 Si 251 251 1 50 1 50 Szi 1 1 21 1 19 0 52 Oso 0 0 56 En 450 400 350 300 1 (38.55 KiB) Viewed 42 times

molecular formula: C14H20o2
there is an ester, there is an aromatic ring
using the IR and NMR, identify all peaks, and interpret and assign the hydrogens to the structure you make, and finally name the structure.

2 Of 1 3 Hd Os 2 Na Van 10 457 2 1 55 1 55 1 54 Si 251 251 1 50 1 50 Szi 1 1 21 1 19 0 52 Oso 0 0 56 En 450 400 350 300 2 (38.55 KiB) Viewed 42 times

2 Of 1 3 Hd Os 2 Na Van 10 457 2 1 55 1 55 1 54 Si 251 251 1 50 1 50 Szi 1 1 21 1 19 0 52 Oso 0 0 56 En 450 400 350 300 3 (28.6 KiB) Viewed 42 times

2 Of 1 3 Hd Os 2 Na Van 10 457 2 1 55 1 55 1 54 Si 251 251 1 50 1 50 Szi 1 1 21 1 19 0 52 Oso 0 0 56 En 450 400 350 300 4 (19.45 KiB) Viewed 42 times

2 OF 1.3 HD OS 2 NA VAN 10 457 2 1.55 1.55 1.54 SI 251 251 1.50 1.50 SZI 1 1.21 1.19 0.52 OSO 0 0.56 en 450 400 -350 300 B (m) 1.19 -250 FO 2.31 E dd) 2.65 Alm) 7128 c(t) 4.94 (m .SE 200 I (m 40 6T 06 -150 -100 -50 0 OBZ 11-01 29988 92 2.72 乃阳山双 - - 16 15 14 ET 12 11 10 9 8 9 5 4 E 2 0 I -2 7 fi (ppm)

450 400 350 300 -250 200 -150 -100 50 16 15 14 13 12 11 10 9 8 6 0

100 39971114 39559312 3000 30271 29725731 29353151 20785260 17300531 14543596 1377.1039 12475347 12035415 1172 2310 115604 1123 0911 109553 1000 105 1103 W320