6. Calculate the ∆Hf for X (g) using the data below. (10
points)
3 X (g) + 2 C (l) → 4 D (g) ∆Hrxn = -175 kJ
∆Hf C(l) = - 105 kJ/mol ∆Hf D (g) = - 215 kJ/mol
DHf for X=
7. (12 points) Calculate ∆Hrxn for
B2H6 (g) + 6 Cl2 (g) → 2 BCl3 (g) + 6 HCl (g)
B2H6 (g) + 6 H2O (l) → 2 H3BO3 (g) + 6 H2 (g) ∆H = -490 kJ
BCl3 (g) + 3 H2O (l) → H3BO3 (g) + 3 HCl (g) ∆H = =110 kJ
∆Hf
HCl (g) ∆H = -90 kJ
6. Calculate the ∆Hf for X (g) using the data below. (10 points) 3 X (g) + 2 C (l) → 4 D (g) ∆Hrxn = -175 kJ ∆Hf C(l) =
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6. Calculate the ∆Hf for X (g) using the data below. (10 points) 3 X (g) + 2 C (l) → 4 D (g) ∆Hrxn = -175 kJ ∆Hf C(l) =
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