2Al(OH)3 + 3H2SO3 → Al2(SO3)3 + 6H2O - What volume of 0.75M H2SO3 is needed to completely consume (neutralize) 25.0g of

Post by **answerhappygod** » Tue May 17, 2022 7:15 am

: 2al Oh 3 3h2so3 Al2 So3 3 6h2o What Volume Of 0 75m H2so3 Is Needed To Completely Consume Neutralize 25 0g Of 1 (14.91 KiB) Viewed 71 times

: 2al Oh 3 3h2so3 Al2 So3 3 6h2o What Volume Of 0 75m H2so3 Is Needed To Completely Consume Neutralize 25 0g Of 2 (28.99 KiB) Viewed 71 times

: 2al Oh 3 3h2so3 Al2 So3 3 6h2o What Volume Of 0 75m H2so3 Is Needed To Completely Consume Neutralize 25 0g Of 3 (28.99 KiB) Viewed 71 times

2Al(OH)3 + 3H2SO3 → Al2(SO3)3 + 6H2O - What volume of 0.75M H2SO3 is needed to completely consume (neutralize) 25.0g of Al(OH)3?

1. Use the following balanced chemical equation to answer the questions below. CH4 + 202 CO2 + 2H2O a) In the reaction, 6.0g of methane (CH4) reacts with 16.0g of oxygen. What is the limiting reagent? b) What is the amount of excess (in grams), of the other chemical? c) Based on the limiting reagent, how many grams of water would be produced?