32. Sodium bicarbonate decomposes at high temperatures according to the following equation: 2 NaHCO3(s) Na2CO3(s) + CO2(
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32. Sodium bicarbonate decomposes at high temperatures according to the following equation: 2 NaHCO3(s) Na2CO3(s) + CO2(
32. Sodium bicarbonate decomposes at high temperatures according to the following equation: 2 NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) At a certain temperature, 50.0 g of NaHCO3 is allowed to react in a 3.0 L evacuated vessel. At equilibrium, the total pressure is 6.25 atm, with some of both solids still present. If 100.0 g of NaHCO3 is allowed to react in the same vessel at the same temperature, what will the pressure be at equilibrium? (A) 6.25 atm (B) 8.84 atm (C) 12.5 atm (D) 25.0 atm
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