A particle’s position changes with time according to x = 8.0 – 7.0 t + 3.0 t^2 – 8.0 t^3 + 0.5 t^4, where x is measured

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answerhappygod
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A particle’s position changes with time according to x = 8.0 – 7.0 t + 3.0 t^2 – 8.0 t^3 + 0.5 t^4, where x is measured

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A particle’s position changes with time according to x = 8.0 –
7.0 t + 3.0 t^2 – 8.0 t^3 + 0.5 t^4,
where x is measured in meters and t is measured in seconds. No
primes for derivatives!!!
a) Write the particle’s velocity as a function of time.
Units!!

b) Write the particle’s acceleration as a function of time.
Units!!

c) Write the particle’s jerk as a function of time. Units!!
d) What is the particle’s initial velocity? Units!!
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