Experiment A3 Lab Report Results Length 1 No. of Time t Period (T) (m) oscillation (s) (s) log1 log T S 0.47 50 68.67 0.

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Experiment A3 Lab Report Results Length 1 No. of Time t Period (T) (m) oscillation (s) (s) log1 log T S 0.47 50 68.67 0.

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Experiment A3 Lab Report Results Length 1 No Of Time T Period T M Oscillation S S Log1 Log T S 0 47 50 68 67 0 1
Experiment A3 Lab Report Results Length 1 No Of Time T Period T M Oscillation S S Log1 Log T S 0 47 50 68 67 0 1 (302.73 KiB) Viewed 34 times
Experiment A3 Lab Report Results Length 1 No Of Time T Period T M Oscillation S S Log1 Log T S 0 47 50 68 67 0 2
Experiment A3 Lab Report Results Length 1 No Of Time T Period T M Oscillation S S Log1 Log T S 0 47 50 68 67 0 2 (100.92 KiB) Viewed 34 times
Experiment A3 Lab Report Results Length 1 No Of Time T Period T M Oscillation S S Log1 Log T S 0 47 50 68 67 0 3
Experiment A3 Lab Report Results Length 1 No Of Time T Period T M Oscillation S S Log1 Log T S 0 47 50 68 67 0 3 (116.16 KiB) Viewed 34 times
Experiment A3 Lab Report Results Length 1 No. of Time t Period (T) (m) oscillation (s) (s) log1 log T S 0.47 50 68.67 0.67 50 83.30 0.87 50 94.39 1.02 50 102.19 1.13 50 107.93

Analysis Plot a graph of log T against log l. This should produce a straight line of slope n and y intercept equal to log k. Explain why this is so. Note that you need not show log T = 0 but you must include log 1 = 0 in order to obtain the y intercept. From the graph, n= log k = k= Hence from equation (A3.2) g=

From the graph calculate the length of a pendulum beating seconds (i.e. one with a period of 2 s). Length = m. Conclusions The actual value of g in Johannesburg is 9,79 m.s-2. Compare this with your measured value. What do you conclude? From equation (A.31) and (A3.2) T = 2π in vg (A3.3) Use the method of dimensional analysis* to find the value of n. Compare this with your value of n.
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