(33%) Problem 3: A convex lens is placed a distance D=15.0 cm in front of a projection screen for the purpose of imaging

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33 Problem 3 A Convex Lens Is Placed A Distance D 15 0 Cm In Front Of A Projection Screen For The Purpose Of Imaging 1 (125.01 KiB) Viewed 52 times

(33%) Problem 3: A convex lens is placed a distance D=15.0 cm in front of a projection screen for the purpose of imaging objects that are a great distance away, but the images appear at an image distance which falls short of the screen. D ed Due to the supporting structures holding the lens and the screen, they may not be easily relocated. A student is assigned the task of placing a concave lens with a focal length FD = -8.4 cm between the first lens and the screen to correct the problem. $ 14% Part (a) Suppose that, prior to the addition of the second lens, di =6.75 cm to the right of the first lens, a converging lens. The student checks that moving objects even farther to the left has no observable impact. What is the focal length. Fc, of the first lens? Fc = 8.4 X Attempts Remain 14% Part (b) The second lens, the diverging lens, is placed between the first lens and the original position of the images, as shown in the figure in the problem statement. The student is told that the image of the first lens becomes the object for the second lens. Which statement below best describes the object for the second lens? The object is a virtual object because the incoming rays converge. ✓ Correct! A 14% Part (c) Given that the second lens has a focal length FD = -8.4 cm, determine the position z as measured to the right of the first lens that results in an image focused on the screen. Your solution must be in the range 0 <I<6.75 cm which places the concave lens between the convex lens and the original image position A 14% Part (d) Suppose that the object is not placed infinitely far to the left, but it is placed at a distance do 1=5.75 m in front of the convex lens. Calculate the image distance, di,1, relative to the first lens, and include the appropriate sign consistent with the standard sign conventions. (Don't include effects of the second lens yet.) A 14% Part (e) The second lens is now added at a position that is a distance r to the right of the first lens using the value for x that you calculated previously. Noting that the image of the first lens becomes the object of the second lens, calculate the object distance, do2, for the second lens. Include the appropriate sign per the standard sign conventions.