Part A A particle carrying 5.0 x 10-7 C of charge is located on the perpendicular bisector of a small dipole, 300 mm from the center of the line joining the two poles of the dipole. The magnitude of the electric force exerted on the particle is 18.0 x 10-6 N. Determine the magnitude of the electric force exerted on the dipole. Express your answer with the appropriate units. 0 μΑ ? F = Value Units Submit Request Answer
1 Review Part A The electric force due to a uniform external electric field causes a torque of magnitude 20.0 x 10-9 N.m on an electric dipole oriented at 30° from the direction of the external field. The dipole moment of the dipole is 7.5 X 10-12 C.m. What is the magnitude of the external electric field? Express your answer with the appropriate units. НА ? E = Value Units Submit Request Answer Part B If the two particles that make up the dipole are 2.5 mm apart, what is the magnitude of the charge on each particle? Express your answer with the appropriate units. μΑ ? 4p = Value Units
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