Could you please help me in solving sections (ii) and (iii) of this question, also please check my answer if it is corre

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Could you please help me in solving sections (ii) and (iii) of
this question, also please check my answer if it is correct or not
in the part (i) and let me know. thanks in advance.

Could You Please Help Me In Solving Sections Ii And Iii Of This Question Also Please Check My Answer If It Is Corre 1 (54.62 KiB) Viewed 57 times

(c) A 4 m by 8 m solar array installed on a flat horizontal surface in Birmingham produces 6000 W of power on Day Number 20. Assuming clear sky conditions under AM1.5 and using relevant equations in the APPENDIX, calculate: (i) The sunrise and sunset times in Birmingham on Day Number 20. (3 marks) (ii) The theoretical amount of solar energy received (in kWh) by the solar array, between sunrise and sunset on this day. (2 marks) (iii) The efficiency of its solar panels. (1 mark)
Solar Angles and Relevant Solar Energy Data 't- = Hour angle, w 612 ) 360° t = time (hours) based on 24-hour clock 24 = Definitions 0 = latitude = 52.5° N for Birmingham, UK D = Day number 2019 Vernal Equinox March 20 (D = 79) 2019 Autumnal Equinox September 23 (D = 266) Zenith angle, Oz cos Oz = sind sing + cosd coso cosw - Angle of declination, s = – 23.45 cos (D+10 X 360° ) 365 Angle of incidence, 0; cos 0;= cosd cos(6-8) + sind sin(0-1) UK sunlight hours data: The UK experiences sunlight for 52% of the hours in a year, which is split in a 3:2 ratio between each half of the year when the equinoxes occur. B = angle of inclination =
Ans:- *ure know that: Sunrise of Sunset occurs when Zenith angle = 0] ور الأعقی 19 ze السمسعاك Also we know that: The latitude (4) of Birmingham is Therefore ; sz. 52.5 N] N Day no. Angle of Declination (8) Z=-23.45 Ces 360 365 (D+10 3= -23.45 cos! (3) (6.8 (20 + (0)] 3 со 365 x - 20.4 Howr angle(s): : خدا 3ه) : Cos ws = Latitude - Tanu. Tana - Tan (52.5) Tan (-20.4) W.61.61 by using the equation below, we can get the (t) value: [ 360 61.01 = WE + 12 E24 tay = 12 24 1x360 24 e tz4 = 16.07 ~ Sunset # tzy 7.93 Sunrise *