B4C+Nb=Nb5B6+Nb4C3

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answerhappygod
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B4C+Nb=Nb5B6+Nb4C3

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B4C+Nb=Nb5B6+Nb4C3
B4c Nb Nb5b6 Nb4c3 1
B4c Nb Nb5b6 Nb4c3 1 (19.65 KiB) Viewed 62 times
B4c Nb Nb5b6 Nb4c3 2
B4c Nb Nb5b6 Nb4c3 2 (19.65 KiB) Viewed 62 times
C. Liquid Hf-Nb alloy infuses into a B.C packed bed and reacts to form a HfBz-HfC- Nb B6-NbĄCs composite or the same boride-carbide precipitates embedded in a Hf- Nb alloy matrix. Determine the mass of Hf and Nb needed to give you sufficient Nb Be and Nb.C, in a niobium metal matrix by adding 20% excess niobium needed for the formation of 1 kg of NbsBe with carbide particles.
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