Question 1 Manning S Equation A A Rectangular Channel With Width 3m Has A Bed Slope Of 1 In 500 And A Mannings N 0 02 1 (59.38 KiB) Viewed 63 times
Question 1. Manning's Equation a) A rectangular channel with width 3m has a bed slope of 1 in 500, and a Mannings n=0.028. Calculate the flow if the water depth is 1.5m b) A trapezoidal channel with base width 4m has side slope 2V:1H and a longitudinal slope of 1 in 800. It has a Manning's n=0.035. Calculate the normal flow depth and the critical flow depth for a discharge of 7.5m/sec c) A 1.2m circular concrete pipe with Manning's n=0.013, laid on a 0.8% slope has a flow depth of 0.7m. Using the circle equations from Lecture 5, calculate the flow and velocity in the pipe. Compare this the value of Q derived from the Chow normal depth chart. d) The channel shown below has a slope of 0.006 and a Manning's n=0.021. 450 f у 450 0.6m 1.8m -1.2m Find the normal depth of flow, and the flow type (sub or super-critical) for flows of : i) 1.35m?/s (which will be in then lower section of the channel) 11) 5.6m/s (which will be in the upper section of the channel)
Calculating the Critical Depth Difficulties of critical depth calculations for a pipe. Ꮎ B(y)=Dsin 2 D2 A(y)=> [21–0+sine] = F D 8 у 0=2 cos- 2y D Q2 Aly) B.(y) = eg. Find the critical depth of a flow of 1m/sec in a 900mm diameter pipe. g D = 0.900 Ycm 0.591 theta, rad 2.502 BCYC), m A(Yc), m^2 V(Yc), m/s 0.854 0.443 2.256 hm 0.911 Q.m3/s 1.000
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