The beam AB is a composite section and is formed by welding a PFC Channell and a universal beam (UB) Section3 (See Table

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The beam AB is a composite section and is formed by welding a PFC Channell and a universal beam (UB) Section3 (See Table

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The Beam Ab Is A Composite Section And Is Formed By Welding A Pfc Channell And A Universal Beam Ub Section3 See Table 1
The Beam Ab Is A Composite Section And Is Formed By Welding A Pfc Channell And A Universal Beam Ub Section3 See Table 1 (171.09 KiB) Viewed 52 times
The Beam Ab Is A Composite Section And Is Formed By Welding A Pfc Channell And A Universal Beam Ub Section3 See Table 2
The Beam Ab Is A Composite Section And Is Formed By Welding A Pfc Channell And A Universal Beam Ub Section3 See Table 2 (62.26 KiB) Viewed 52 times
The Beam Ab Is A Composite Section And Is Formed By Welding A Pfc Channell And A Universal Beam Ub Section3 See Table 3
The Beam Ab Is A Composite Section And Is Formed By Welding A Pfc Channell And A Universal Beam Ub Section3 See Table 3 (25.93 KiB) Viewed 52 times
The Beam Ab Is A Composite Section And Is Formed By Welding A Pfc Channell And A Universal Beam Ub Section3 See Table 4
The Beam Ab Is A Composite Section And Is Formed By Welding A Pfc Channell And A Universal Beam Ub Section3 See Table 4 (45.3 KiB) Viewed 52 times
The beam AB is a composite section and is formed by welding a PFC Channell and a universal beam (UB) Section3 (See Table 1) together as shown in Figure 2(b). The individual sectional properties are given in Figure 2(c) and (d) where x and y. indicate centroidal axes. P С a B. А x T a L/2 -L/2 (a) (b) Section a-a X y (d) PFC Channel (c) UB section WANNA Figure 2 Figure 2
Section X 1 ty mm 11.9 11.2 Table 1. Sectional properties UB Section А d bf у tt mm2 mm mm mm 16000 612 229 19.6 14500 607 228 17.3 13000 602 228 14.8 11800 533 209 15.6 10500 528 209 13.2 2 اداب الماما Ixe (x108 mm) 986 875 761 554 477 610UB125 610UB113 610UB101 530UB92.4 530UB82 Iyo (x108 mm) 39.3 34.3 29.3 23.8 20.1 3 اے اے 4 10.6 10.2 9.6 5 X y mm2 tt mm 17.5 PFC Channel A d br mm mm 7030 380 100 5110 300 90 4520 250 90 Section 380PFC 300PFC 250PFC 1 ty mm 10 8 - 27.5 27.2 28.6 1xB (x108 mm) 152 72.4 45.1 lyo (x108 mm) 6.48 4.04 3.64 2 3 16 15 8
a) Determine the bending moment equation (in terms of x, P, and L) at a section located at a distance x from the left support d’y = ΕΙ = M = dx² b) Determine the slope equation in the terms of in term of x, P and L dy ΕΙ dx ΕΙΘ - =
c) Determine the maximum deflection in term of P and L :. El Ymax = d) ) Determine the moment of inertia Ixx with respect to the centroidal axes. Ixx = x106mm4
Hence, determine the maximum deflection of the beam having a length of 3 m long and applied the load of 20 kN. Use E =200GPa. Ymax = mm (insert "-" sign if the deflection is downward). Submit part Unanswered f) Hence, determine the slope at A 04 rad (insert "-" sign if the slope is clockwise rotation). Submit part Unanswered
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