Answer Happy • Given: A(g) + B(g) - D(g): AH = 56kJ/mol; the enthalpy change for 3A(g) + 3B(g) + 3D(g) is: = A. -168 B. 168 C-56

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Given: A(g) + B(g) - D(g): AH = 56kJ/mol; the enthalpy change for 3A(g) + 3B(g) + 3D(g) is: = A. -168 B. 168 C-56

Posted: Tue Nov 16, 2021 6:19 am

by answerhappygod

: Given A G B G D G Ah 56kj Mol The Enthalpy Change For 3a G 3b G 3d G Is A 168 B 168 C 56 1 (68.2 KiB) Viewed 68 times

Given: A(g) + B(g) - D(g): AH = 56kJ/mol; the enthalpy change for 3A(g) + 3B(g) + 3D(g) is: = A. -168 B. 168 C-56