Given: A(g) + B(g) - D(g): AH = 56kJ/mol; the enthalpy change for 3A(g) + 3B(g) + 3D(g) is: = A. -168 B. 168 C-56

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

Given: A(g) + B(g) - D(g): AH = 56kJ/mol; the enthalpy change for 3A(g) + 3B(g) + 3D(g) is: = A. -168 B. 168 C-56

Post by answerhappygod »

Given A G B G D G Ah 56kj Mol The Enthalpy Change For 3a G 3b G 3d G Is A 168 B 168 C 56 1
Given A G B G D G Ah 56kj Mol The Enthalpy Change For 3a G 3b G 3d G Is A 168 B 168 C 56 1 (68.2 KiB) Viewed 67 times
Given: A(g) + B(g) - D(g): AH = 56kJ/mol; the enthalpy change for 3A(g) + 3B(g) + 3D(g) is: = A. -168 B. 168 C-56
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Top
Post Reply

Return to “Archived Questions & Answers”