especially the calculation of Re. and please explain(the aswer bellow use a wrong unit to calculate Re, and please calculate it again using si unit). and please tell me how to calculate F here in details. I don't know why F = 0.046/Re^0.2(I don't know where 0.046 and 0.2 come from.)
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Am PV-15V $(schedule wo) Bensily. 820, Ahmev?, Viscocibly so oppiso = 0.6ea10 7 318 % Head Bestselal the nominal diameter of the rochien pipe is equivaled length=13m 393941 The nominal diameter of dischange life is 2 (schedule 80 equivalent length: 1370 PP flow rate 6 - love gallos/br0-4 drs 0-637: Pec Pump head required in the system is Re End AL 0-037 (0-1615 )*xv VER BFH/Sec Re: 87481-811 XD-1615 D.087 Re: 136697.5 Elow in bibe dine i tumbuteat flous because Rey 4000 0:0 032AV F30-046 (Tabel and duel elen 1936) lata Im Pump 7. Erachion factor F: 0.04 R2 : 0.046 (156697.532 24301103
Eochen Fachon F och 24.3213 -0.046 (156697-590-2 Major head lors - FLV? agd R.: 439 X10 ex (1370 +39,37) X -6m 2x32.7XXIS bez 192-19 Ft Minar head loss consist of 3-90 elbow, scrit and lenbrance lors 190 ellow -0-75 FO Kecil ! bR 3 kv* +050 V2 + 29 29 99 = 3X0-25 (-301) 10:50 22.19 99917 2% 2.172 1-80), 01:20 +1 -M 29 14.69 14 bR2 - 030737 applying energy equation P 24 * +2 - R + +224 benabre - M Pump 7.734 M +656 +39.37 +1.9917+ 874x32 974x32.17 0-30931 Pompa HPump - 3539547 Mpump = 1076mbers Buswu which Rumb developed Lalm = 1969 Psi Popa M Pump - 87.4 73.2.47735395 P: 99518.(38 Corvol in Psi P=691161. Psial 14-69 P=47. 8)
maximal NPSM in Rl is brs = FLV2 + 2x0.7562 29d 29 +0.5v² २१ 0 = 0.037) -7 4 (0.255)? xv V :0.726 ft/sec brs = 4.32 x103 x39-37(0.726)2 2x32.17X0255 bes = 5.46*10*9+1660-7292 +05(0-728) 2 X32.17 2x32.17 bRs = 0.02 18ff NPSH =P 39 Pv 89 + V² 29 113.79 313.26 + 9721*32.17 10726 2x92-17 87.4 x 32.17 - NPSM -0.292967
Question #3: We are pumping acid (density 874 viscosity 0.09 poise, Py = 15 KPa) from storage tank, which is in the basement of the factory, to another tank which is in the top floor. The head pressure in the storage tank is 400 mmHg and the head pressure in the top tank is 1 atm. The nominal diameter of the suction pipe is 3" (schedule 40), and its equivalent length is 12 m: the nominal diameter of the discharge pipe is 2" (schedule 80) and its equivalent length is 1370 ft. All pipes can be regarded as "smooth pipe". The pipe is located 3 m above the acid level in the storage tank, and we can assume that the level of acid in the storage tank is kept constant. The volumetric flow rate in the system is 1000 us callon All other details of the system are displayed in the scheme attached next page after this question. hr a. What is the pump head (in m) required in this system? b. What is the pressure which the pump develops (in atm? c. What is the maximal NPSH manufacturer which is allowed for the pump (in ft)? 2 12 m 400 mm 2 m
lbm We are pumping acid (density 87.4 viscosity 0.09 poise, Py = 15 KPa) from storage tank, which is in the basement of the factory, to another tank which is in the top floor. The head pressure in the storage tank is 400 mmHg, and the head pressure in the top tank is 1 atm. The nominal diameter of the suction pipe is 3" (schedule 40), and its equivalent length is 12 m; the nominal diameter of the discharge pipe is 2" (schedule 80) and its equivalent length is 1370 ft. All pipes can be regarded as "smooth pipe". The pipe is located 3 m above the acid level in the storage tank, and we can assume that the level of acid in the storage tank is kept constant. The volumetric flow rate in the system is 1000 US Gallon All other details of the system are displayed in the scheme attached next page after this question. hr a. What is the pump head (in m) required in this system? b. What is the pressure which the pump develops (in atm)? c. What is the maximal NPSHmanufacturer which is allowed for the pump (in ft)?
1 atm m m 12 m 400 mmHg 2 m