- A Beam Rests Upon Two Springs When Force F 740 N Is Applied To The Beams The Springs Compress And The Beam Becomes P 1 (159.4 KiB) Viewed 51 times
- A Beam Rests Upon Two Springs When Force F 740 N Is Applied To The Beams The Springs Compress And The Beam Becomes P 2 (44.37 KiB) Viewed 51 times
A beam rests upon two springs. When force F = 740 N is applied to the beams, the springs compress and the beam becomes perfectly horizontal F Li L2 А www. B Geometry L=1.5 m L2=1.5 m Spring Constants: ka=23 kN/m kB =57 kN/m i. Determine the magnitude of force acting on the beam from spring A. 1. Determine the magnitude of force acting on the beam from spring B. TIL Determine is the deflection of spring A. (ie. what is the distance that spring A is squished?) in. Determine is the deflection of spring B.(i.e. what is the distance that spring B is squished?) V. Force F is then removed and the springs decompress and return to their resting position. The beam is no longer horizontal. Determine the angle of tilt 0 of the beam from the horizontal Assumptions you can make: The beam is massless and rigid. • The springs can only move in the vertical direction
Part E - Part E Force F is then removed and the springs decompress and return to their resting position. The beam is no longer horizontal Determine the angle of tilt 8 of the beam from the horizontal Express your answer in units of degrees to three significant figures