a = 2 W/m² 91 = 1 W/m 42 = 4 W/m3 h=3 W/m².K, T. = 100°C 2A=0 IB=1 a Consider a one dimensional rod of length L = 1, dis

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answerhappygod
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a = 2 W/m² 91 = 1 W/m 42 = 4 W/m3 h=3 W/m².K, T. = 100°C 2A=0 IB=1 a Consider a one dimensional rod of length L = 1, dis

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A 2 W M 91 1 W M 42 4 W M3 H 3 W M K T 100 C 2a 0 Ib 1 A Consider A One Dimensional Rod Of Length L 1 Dis 1
A 2 W M 91 1 W M 42 4 W M3 H 3 W M K T 100 C 2a 0 Ib 1 A Consider A One Dimensional Rod Of Length L 1 Dis 1 (43.61 KiB) Viewed 40 times
a = 2 W/m² 91 = 1 W/m 42 = 4 W/m3 h=3 W/m².K, T. = 100°C 2A=0 IB=1 a Consider a one dimensional rod of length L = 1, discretized into N = 2 blocks of equal length Ax = L/N. The right end of the rod is exposed to ambient air at temperature To. 100° C and heat transfer coefficient of h 3 W/m².K, whereas the left end has a heat flux boundary condition in the direction indicated by the arrow. The thermal conductivity of the rod is k = 1 W/(m.K). A spatially-varying energy source embedded in the rod is indicated by ù, whose numerical value at the block-center is given in the figure. 1. Assuming steady state conditions, write down the continuous form of the energy equation for each block. 2. Then using the finite difference approximation, find the numerical values of {T1, T2} at the centers the two blocks.
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