(a) Figure Q7 shows a cross sectional view of a roof. Using the dimensions in the figure and the thermal properties of t

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

(a) Figure Q7 shows a cross sectional view of a roof. Using the dimensions in the figure and the thermal properties of t

Post by answerhappygod »

A Figure Q7 Shows A Cross Sectional View Of A Roof Using The Dimensions In The Figure And The Thermal Properties Of T 1
A Figure Q7 Shows A Cross Sectional View Of A Roof Using The Dimensions In The Figure And The Thermal Properties Of T 1 (74.89 KiB) Viewed 51 times
(a) Figure Q7 shows a cross sectional view of a roof. Using the dimensions in the figure and the thermal properties of the materials show that the overall U- value is approximately 0.180W/m2K [10 marks] Resistance of outside boundary layer........ ..0.13m2K/W Resistance of inside boundary layer. ..0.05m²K/W Thermal conductivity of roof tile. .1.19 W/mK Thermal conductivity of plywood.. .0.14 W/mK Thermal conductivity of insulation .... ...0.030 W/mK Thermal conductivity of plasterboard. ...0.160 W/mK (b) The roof in part (a) is covered with a uniform blanket of snow. Calculate the thickness of snow that would reduce the total U-value for the roof to 0.08W/m²K. [6 marks] Thermal conductivity of snow ....0.05 W/mK (c) The roof has a total area of 150m². Calculate the heat lost by conduction with and without the layer of snow on the roof [4 marks] Internal room temperature ..20°C External air temperature .-6°C Roof Tile 20mm 25mm 150mm Insulation 20mm Plasterboard 10mm Plywood
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply