o ok 7=17 i. V, с 7 = 17 w OK 10 (a) (

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answerhappygod
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o ok 7=17 i. V, с 7 = 17 w OK 10 (a) (

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7.1 the basic series resonant inverter in figure 7.1a It has L1 = L2= l =25 uH, c =2 uF, and R =4 ohm. The input CD voltage is v, 220 v and the output frequency is fo = 6.5 KHZ.
The deactivation time of the transistors is toff= 15 us. Determine (a) the available toff (or circuit) deactivation time; (b) the maximum permissible frequency fmax; (c) the peak to peak voltage VPP of the capacitor, and (d) the peak current of the IP charge. (e) draw the graph of the instantaneous current Io,(t) of the charge, the capacitor voltage Vc(t) and the supply CD current is(t). (f) calculate the RMS load current lo; (g) the output power Po;(h) the average supply current Is(t); and (i) the average, peak, and RMS currents of the transistor.
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o ok 7=17 i. V, с 7 = 17 w OK 10 (a) (
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