vt := 39-10-3 i:= 0..4 .7 0.624 vd .75 Id(vd) := 10-10-12 vt e -1 vdi:= .8 2.248 Id(vdi) = 8.102-10-3 29.201 .85 .9 vd

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answerhappygod
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vt := 39-10-3 i:= 0..4 .7 0.624 vd .75 Id(vd) := 10-10-12 vt e -1 vdi:= .8 2.248 Id(vdi) = 8.102-10-3 29.201 .85 .9 vd

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Vt 39 10 3 I 0 4 7 0 624 Vd 75 Id Vd 10 10 12 Vt E 1 Vdi 8 2 248 Id Vdi 8 102 10 3 29 201 85 9 Vd 1
Vt 39 10 3 I 0 4 7 0 624 Vd 75 Id Vd 10 10 12 Vt E 1 Vdi 8 2 248 Id Vdi 8 102 10 3 29 201 85 9 Vd 1 (4.57 KiB) Viewed 32 times
Vt 39 10 3 I 0 4 7 0 624 Vd 75 Id Vd 10 10 12 Vt E 1 Vdi 8 2 248 Id Vdi 8 102 10 3 29 201 85 9 Vd 2
Vt 39 10 3 I 0 4 7 0 624 Vd 75 Id Vd 10 10 12 Vt E 1 Vdi 8 2 248 Id Vdi 8 102 10 3 29 201 85 9 Vd 2 (52.34 KiB) Viewed 32 times
Vt 39 10 3 I 0 4 7 0 624 Vd 75 Id Vd 10 10 12 Vt E 1 Vdi 8 2 248 Id Vdi 8 102 10 3 29 201 85 9 Vd 3
Vt 39 10 3 I 0 4 7 0 624 Vd 75 Id Vd 10 10 12 Vt E 1 Vdi 8 2 248 Id Vdi 8 102 10 3 29 201 85 9 Vd 3 (69.85 KiB) Viewed 32 times
Vt 39 10 3 I 0 4 7 0 624 Vd 75 Id Vd 10 10 12 Vt E 1 Vdi 8 2 248 Id Vdi 8 102 10 3 29 201 85 9 Vd 4
Vt 39 10 3 I 0 4 7 0 624 Vd 75 Id Vd 10 10 12 Vt E 1 Vdi 8 2 248 Id Vdi 8 102 10 3 29 201 85 9 Vd 4 (27.09 KiB) Viewed 32 times
-Calculate the resistance in dc for point C
-Calculate the average resistance between A and D
-Calculate the instantaneous resistance at C using the vt
vt := 39-10-3 i:= 0..4

.7 0.624 vd .75 Id(vd) := 10-10-12 vt e -1 vdi:= .8 2.248 Id(vdi) = 8.102-10-3 29.201 .85 .9 vd = 7,0.705 ...95 105.24

0.111 0.0881 Id(vd) 0.0604 Id(vdi) Ooo 0.0447 с 0.022 В B A A 0.62 0.73 0.84 0.95 vd, vdi

vd(V) Id(A) 0.75 0.0022481 A B B 0.8 0.0081022 с 0.85 0.029201 D 0.9 0.10524
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