- 1 (20.35 KiB) Viewed 62 times
- 2 (20.35 KiB) Viewed 62 times
- 3 (22.31 KiB) Viewed 62 times
- 4 (29.43 KiB) Viewed 62 times
- 5 (26.44 KiB) Viewed 62 times
- 6 (27.53 KiB) Viewed 62 times
Problem 2: Convert the current sources in Fig. 8.109 to voltage sources. 1.5 A 4.7 ΚΩ o 30ZR, R 0 ) 6 mA (a) FIG. 8.109
Problem 3: For the configuration in Fig. 8.111: a. Convert the current source and 6.8 resistor to a voltage source. b. Find the magnitude and direction of the current li. C. Find the voltage Vab and the polarity of points a and b. R2 w 6.82 R M 102 I = 2A E = 12 V R3 39 Q Vab 1 FIG. 8.111
Problem 4 : Convert the voltage sources in Fig. 8.114 to current sources. a. Find the voltage Vab and the polarity of points a and b. b. Find the magnitude and direction of the current 13. 13 Ri 312 R2 222 120 BRAVO 612 R3 + E =9v E2 = - 20 V + FIG. 8.114
Problem 5: For the network in Fig. 8.115: a. Convert the voltage source to a current source. b. Reduce the network to a single current source, and determine the voltage V1. c. Using the results of part (b), determine V2. d. Calculate the current l2. + V2 - R2 8 mA 2.2 ΚΩ VR, 36.8kQ )3 mA = 12 V FIG. 8.115