Problem 5: Frequency Domain Circuit Analysis (15 pts) 2mH 000 102 w ZTH w оа Vs(t) 1mF VTH(t) ob оь Original Thevenin Eq

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Problem 5: Frequency Domain Circuit Analysis (15 pts) 2mH 000 102 w ZTH w оа Vs(t) 1mF VTH(t) ob оь Original Thevenin Eq

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Problem 5: Frequency Domain Circuit Analysis (15 pts) 2mH 000 102 w ZTH w оа Vs(t) 1mF VTH(t) ob оь Original Thevenin Equivalent In the above circuits, vs(t) = 2cos 1000t. Wz1000 a) Convert the inductor and capacitor into impedance (Z and Zc). (2 pts) IZL=j 2 o ZL = 5wL = j X 1000 X ZX103 - j 2 st Zc je JX2X1000 x103 = -10 Z = Z=-j1 2 b) Find the Thevenin Equivalent voltage VTH in both frequency and time domain. (6 pts)

c) Find the Thevenin Equivalent impedance ZTH. (4 pts) d) In order to extract the maximum average power from the source, find the loading impedance should be attached between "a" and "b". (3 pts)
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