Note: that given R2 = 0.5 ohm is the actual rotor resistance, R2 referred to the stator side is 2 ohms. Please have work
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Note: that given R2 = 0.5 ohm is the actual rotor resistance, R2 referred to the stator side is 2 ohms. Please have work
Note: that given R2 = 0.5 ohm is the actual rotor resistance, R2 referred to the stator side is 2 ohms. Please have work reflect given solutions to receive thumbs up. Thanks! a. T = 60Nm, b. I= 8.878A, c. Tst = 168.52 Nm, d. Ist = 59.4A, e. Vi=88.4V, Vi=44.2V, Vi L-L = 76.5566V, f.a T = 60 Nm, f.b 12 = 11.9194 A using Vi’, f.c T2st(new)=144.581 Nm, f.d 12st(new)= 40.4583A, g. Pr=2.4592e+3 W. Part h. can be ignored. A three-phase, 480 V, six-pole, Y-connected, 60 Hz, 10 kW induction motor is driving a constant torque load of 60 Nm. The parameters of the motor are: R1 = 0.4 12, R2 = 0.52, Xeq = 40, N / N2 = 2 Calculate the following: a. Motor torque. b. Motor current c. Starting torque d. Starting current
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