A finite line of charge with uniform charge density p extends along the Z-axis between z=-1/2 and z = L/2, as shown in F

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answerhappygod
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A finite line of charge with uniform charge density p extends along the Z-axis between z=-1/2 and z = L/2, as shown in F

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A Finite Line Of Charge With Uniform Charge Density P Extends Along The Z Axis Between Z 1 2 And Z L 2 As Shown In F 1
A Finite Line Of Charge With Uniform Charge Density P Extends Along The Z Axis Between Z 1 2 And Z L 2 As Shown In F 1 (46.43 KiB) Viewed 61 times
A finite line of charge with uniform charge density p extends along the Z-axis between z=-1/2 and z = L/2, as shown in Figure A1a below. (1) (2) () (ii) Determine an expression for the differential electric field, de, at any point, P(r, 0, 0), on the x-y plane due to this line of charge. Using your result from (i), show that can be defined as the following: р L/2 E = ar [V/m) 2118gr r2 + (L/2) If the line of charge now extends to infinity, provide a new expression for E, by using your result from (i). (2) (iii) (1) z = + 1/2 Some useful identities: z = sin e R r cos e R If R IN | 히 N . € -= tane r P(r, 0,0) dz = R cos de dz = r sec? o de Z=-L/2 Figure A1a
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