Given a binary tree with the following rules: root.val == 0 If treeNode.val == x and treeNode.left != null, then treeNod

[answerhappygod]

Given a binary tree with the following rules: root.val == 0 If
treeNode.val == x and treeNode.left != null, then treeNode.left.val
== 2 * x + 1 If treeNode.val == x and treeNode.right != null, then
treeNode.right.val == 2 * x + 2 Now the binary tree is
contaminated, which means all treeNode.val have been changed to -1.
Implement the FindElements class: FindElements(TreeNode* root)
Initializes the object with a contaminated binary tree and recovers
it. bool find(int target) Returns true if the target value exists
in the recovered binary tree. /** * Definition for a binary tree
node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode
*right; * TreeNode() : val(0), left(nullptr), right(nullptr) {} *
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} *
TreeNode(int x, TreeNode *left, TreeNode *right) : val(x),
left(left), right(right) {} * }; */ class FindElements { public:
FindElements(TreeNode* root) { } bool find(int target) { } }; /** *
Your FindElements object will be instantiated and called as such: *
FindElements* obj = new FindElements(root); * bool param_1 =
obj->find(target);