doc dt -321 + 4.C2 Find the general solution of the system 0.02 21 - 22 dt Oxi(t) = -3C1e2+ + 2C%e-2, Iy(t) = 4C1e2- Cze

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Doc Dt 321 4 C2 Find The General Solution Of The System 0 02 21 22 Dt Oxi T 3c1e2 2c E 2 Iy T 4c1e2 Cze 1 (24.46 KiB) Viewed 29 times

doc dt -321 + 4.C2 Find the general solution of the system 0.02 21 - 22 dt Oxi(t) = -3C1e2+ + 2C%e-2, Iy(t) = 4C1e2- Cze-2 1 O xi(t) = Cjet - 2Cze-5, 12(t) = C et + Cze-5t O2(t) = e2t (2Cị sin 5t + C, cos 5t), (t) = 2(-C; sin 5t + C, cos 5t) 21 =e =e Oz(t) = e 2* (Ci sin 3t - C2 cos 3t), 22(t) = e 2 (C; sin 3t + C2 cos 3t) O 21(t) = Ciet - 2025, 22(t) = Cie + + Cet