Step 2 Let C = {1,x, *} be the standard basis for P, Since p(x) = 1 + 2x - 7x, we have the following coordinate vector.

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answerhappygod
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Step 2 Let C = {1,x, *} be the standard basis for P, Since p(x) = 1 + 2x - 7x, we have the following coordinate vector.

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Step 2 Let C 1 X Be The Standard Basis For P Since P X 1 2x 7x We Have The Following Coordinate Vector 1
Step 2 Let C 1 X Be The Standard Basis For P Since P X 1 2x 7x We Have The Following Coordinate Vector 1 (58.35 KiB) Viewed 27 times
Step 2 Let C = {1,x, *} be the standard basis for P, Since p(x) = 1 + 2x - 7x, we have the following coordinate vector. [P(x)]- -7 Further, we have the following 10 D 01 C- 0 001 Step Recall that row reduction applied to the n x 2n augmented matrix (BIC) produces the following, [BIC) 09. We have 1 24 B-1014 and C- 1 00 010 D01 DO 1 Create the augmented matrix [BIC and row reduce it such that the left side of the augmented matrix is transformed into the 3 x 3 identity matrix. 124 100 [8]] = 0 14 010 001 001 100 010 OD1 1 -2 0 0 1 4 0 1 1 Therefore, the change of basis matrix P8.c from C to B is as follows. -2 1 -2 PB---10 4 - 1 D 0 1 1 Step 4 Recall that p(xls -P8-CP(x)]c. We previously determined the following 1-24 PB-00 0 1 [p(x)lc LO 0 1 Use these to calculate ( P18 [P(x)]3 - Pg. Colc :) -[ 1 0 0 -2 4 1-4 0 1 1x X -7 Submit Skin Iyou cannot come back )
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