- 12 Let A Be The Matrix Below Solve X Ax 4 3 A 6 2 4 66 1 A X T C E Cos 3t Sin 3t 3 3 2 2 1 B X T 1 (49.6 KiB) Viewed 28 times
12. Let A be the matrix below. Solve x' = Ax. 4 -3 A= 6 -2 4-66 1 a. X(t) = C,e' cos(3t) - sin(3t) (3 + 3) 2 2 1 b. X(t)
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12. Let A be the matrix below. Solve x' = Ax. 4 -3 A= 6 -2 4-66 1 a. X(t) = C,e' cos(3t) - sin(3t) (3 + 3) 2 2 1 b. X(t)
12. Let A be the matrix below. Solve x' = Ax. 4 -3 A= 6 -2 4-66 1 a. X(t) = C,e' cos(3t) - sin(3t) (3 + 3) 2 2 1 b. X(t)=Ce' cos(3) sin(3) + (3) 2 "[cont39) -sis ()]+= Q (*c*cos(z)(?) sincro() 2 b. xo39 » ) 09]+c«couv()+sincro(3) 30)=C[como() - simeo()]+c="[costo (9)+ simo?)] costoſ O C)-sino()]+cze " (costo()+sinco(0) * Q] 2 0 2 c. x(tC,e?' (t) () ) 1 1 1 2 2 d. x(t) = C,e cos(t) t) ) 1 1 e. None of these
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