D = 4n Σ2 - 4(Σα)? Σα 2. The average of the x's is ī= out 4n. so x =n·ī. Rewrite the determinant D substituting x = nã a

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D = 4n Σ2 - 4(Σα)? Σα 2. The average of the x's is ī= out 4n. so x =n·ī. Rewrite the determinant D substituting x = nã and factor = n Remember, we need to show that this is positive in order to be sure that our m and b minimize the sum of squared residuals E(m,b). To show that, consider the sum of the squares of deviations between each x value and the average of all x's: (x – )2 = (x2 – 2x7 +) = { x2 – 22 _æ+nī? =