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Temperature is used to measure the output of a production process. When the process is in control, the mean of the process is = 121.5 and the standard deviation is o=0.3. (a) Compute the upper and lower control limits if samples of size 6 are to be used (Round your answers to two decimal places.) UCL LC Construct the chart for this process. 122.50 122.25 122.00 121.75 121.30 121.25 121.00 120.75 UCL UCI. Sample Mean x Sample Mean 122.50 + 122.25 122.00 121.75 121.50 121.25 121.00 120.75 LCL LCL 10 8 10 Sample Number Sample Number UCL UCL Sample Mean x 122.50 122 25 122.00 121.75 121.50 121.25 121.00 120.75 Sample Mean X 122.50 + 122.25 122.00 121.75 121.50 121.25 121.00 120.75 LCL LCL 4 6 8 10 2 4 8 10 Sample Number Sample Number
(b) Consider a sample providing the following data. 121.8 121.2 122.1 121.7 | 121.4 122.2 Compute the mean for this sample. (Round your answer to two decimal places.) Is the process in control for this sample? Yes, the process is in control for the sample. No, the process is out of control for the sample. (c) Consider a sample providing the following data. 122.3 121.7 121.6 122.2 122.5 129.0 Compute the mean for this sample. (Round your answer to two decimal places.) Is the process in control for this sample? Yes, the process is in control for the sample. No, the process is out of control for the sample.
You may need to use the appropriate appendix table or technology to answer this question, Product filling weights are normally distributed with a mean of 100 grams and a standard deviation of 20 grams. (a) Develop the control limits for the chart for a sample of size 10. (Round your answers to two decimal places.) UCL = 159.49 LC Develop the control limits for the chart for a sample of size 20. (Round your answers to two decimal places.) UCL - LCL Develop the control limits for the chart for a sample of size 30. (Round your answers to two decimal places.) UCL = Lai (b) What happens to the control limits as the sample size is increased? The LC comes closer to the process mean and the UCL moves farther from the process mean as the sample size is increased. Both control limits move farther from the process mean as the sample size is increased. The sample size does not affect the control limits. The UCL comes closer to the process mean and the LCL moves farther from the process mean as the sample size is increased. Both control limits come closer to the process mean as the sample size is increased. (c) What happens when a Type I error is made? The process will be declared in control and allowed to continue when the process is actually out of control. The process will be declared out of control and adjusted when the process is actually in control. (d) What happens when a Type II error is made? The process will be declared in control and allowed to continue when the process is actually out of control. The process will be declared out of control and adjusted when the process is actually in control.
(e) What is the probability of a Type I error for a sample of size 10? (Round your answer to four decimal places.) What is the probability of a Type I error for a sample of size 20? (Round your answer to four decimal places.) What is the probability of a Type I error for a sample of size 307 (Round your answer to four decimal places.) ) What is the advantage of increasing the sample size for control chart purposes? What error probability is reduced as the sample size is increased? Increasing the sample size always increases the likelihood that the process is in control and reduces the probability of making a Type II error. Increasing the sample size always increases the likelihood that the process is in control and reduces the probability of making a Type I error. Increasing the sample size provides a more accurate estimate of the process mean and reduces the probability of making a Type I error. Increasing the sample size provides a more accurate estimate of the process mean and reduces the probability of making a Type II error.
Hello! please answer all parts to the question clearly please its sometimes hard to understand the experts please thank
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Hello! please answer all parts to the question clearly please its sometimes hard to understand the experts please thank
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