- The Marketing Manager Of A Branch Office Of A Local Telephone Operating Company Wants To Study Characteristics Of Reside 1 (13.26 KiB) Viewed 26 times
0.01 0.025 0.1 0.75 0.95 0.99 Critical Values of Chi Squared Cumulative Probabilities Upper-Tail Areas (alpha) Degrees of Freedom 0.005 0.995 0.05 0.95 0.25 0.75 0.9 0.1 0.975 0.025 0.99 0.975 0.9 0.25 0.05 0.01 1 0.004) 0.016 0.102 3.841 5.024 6.635 1.323 2.773 2.706 4.605 2 0.01 0.02 0.103 5.991 9.21 3 0.072 0.115 0.352 0.211 0.584 1.064 0.575 1.213 1.923 4.108 6.251 7.815 7.378 9.348 11.143 11.345 0.001 0.051 0.216 0.484 0.831 1.237 1.69 4 0.207 0.711 5.385 7.779 0.297 0.554 9.488 13.277 15.086 5 0.412 1.1451 2.675 6.626 11.07 12.833 9.236 10.645 6 0.676 0.872 1.635 3.455 7.841 12.592 14.449 16.812 1.61 2.204 2.833 3.49 7 0.989 2.1671 4.255 9.0371 12.017 14.067 16.013 18.475 1.239 1.646 8 2.18 10.219 13.362 15.507 17.535 20.09 1.344 1.735 2.733 3.325 5.071 5.899 9 2.7 11.389 14.684 16.919 19.023 2.088 2.558 10 2.156 3.247 3.94 6.737 12.549 15.987 18.307 20.483 11 4.575 7.584 17.275 19.675 21.92 2.603 3.074 3.053 3.571 4.107 3.816 4.404 12 5.226 4.168 4.865 5.578 6.304 7.042 7.79 8.547 13.701 14.845 15.984) 18.549 23.337 8.438 9.299 10.165 21.026 22.362 21.666 23.209 24.725 26.217 27.688 29.141 30.578 32 13 24.736 3.565 4.075 4.601 14 4.66 17.117 26.119 15 5.009 5.629 6.262 6.908 7.564 5.892 6.571 7.261 7.962 8.6721 11.037 5.229 5.812 6.408 27.488 23.685 24.996 26.296 16 5.142 9.312 19.812 21.064 22.307 23.542 24.769 25.989 27.204 18.245 19.369 20.489 21.605 17 11.912 12.792 13.675 5.697 10.085 27.587 28.845 30.191 31.526 33.409 18 6.265 7.015 8.231 9.39 10.865 34.805 28.869 30.144 19 6.844 7.633 10.117 32.852 8.907 9.591 11.651 12.443 14.562 15.452 36.191 37.566 20 8.26 10.851 28.412 31.41 22.718 23.828 24.935 26.039 7.434 8.034 8.643 11.591 29.615 21 22 32.671 8.897 9.542 10.283 10.982 13.24 14.041 16.344 17.24 34.17 35.479 36.781 38.076 12.338 30.813 33.924 38.932 40.289 41.638 42.98 23 9.26 11.689 13.091 27.141 32.007 35.172 10.196 10.856 24 9.886 13.848 36.415 39.364 14.848 15.659 16.473 17.292 33.196 34.382 25 10.52 11.524 37.652 28.241 29.339 30.435 14.611 15.379 18.137 19.037 19.939 20.843 21.749 22.657 12.401 13.12 13.844 14.573 15.308 40.646 41.923 44.314 45.642 26 11.16 35.563 38.885 27 16.151 31.528 40.113 43.195 11.808 12.461 12.198 12.879 13.565 14.256 14.953 28 16.928 41.337 18.114 18.939 19.768 20.599 36.741 37.916 39.087 40.256 29 46.963 48.278 49.588 50.892 13.121 13.787 16.047 16.791 32.62 33.711 34.8 17.708 18.493 23.567 24.478 44.461 45.722 46.979 42.557) 43.773 30
a. At the 0.10 level of significance, is there evidence that the population standard deviation is different from $12.15? State the null and alternative hypotheses. Choose the correct answer below. O A. Ho: 02 $9.25 OB. Ho: 6 = $9.25 H: 0<59.25 H:0# $9.25 0C. Hp: 02$12.15 OD. Ho: os $12.15 H: 0<$12.15 H: 0> $12.15 O E. Ho: 05 $9.25 OF. Ho: 0= $12.15 Hy: > $9.25 Hy: 0#$12.15 Determine the critical value(s). The critical value(s) isare) (Round to three decimal places as needed. Use a comma to separate answers as needed.) Determine the test statistic, XSTAT- X'STAT -O (Round to three decimal places as needed.) State your conclusion Ho. There is evidence that the population standard deviation is different from $12.15. b. What assumption do you need to make in order to perform this test? O A. It must be assumed that the distribution of the data in the population is skewed. O B. It must be assumed that the distribution of the data in the population is uniform. OC. It must be assumed that the distribution of the data in the population is normal. c. Compute the p-value in (a) and interpret its meaning. p-value = p0 (Round to four decimal places as needed.)