- A Genetic Experiment Involving Peas Yielded One Sample Of Offspring Consisting Of 413 Green Peas And 167 Yellow Peas Us 1 (64.06 KiB) Viewed 23 times
- A Genetic Experiment Involving Peas Yielded One Sample Of Offspring Consisting Of 413 Green Peas And 167 Yellow Peas Us 2 (50.61 KiB) Viewed 23 times
A genetic experiment involving peas yielded one sample of offspring consisting of 413 green peas and 167 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? A. Ho: p=0.24 H:p>0.24 0 C. Ho: p = 0.24 H:p<0.24 *E. Ho: p=0.24 H:p#0.24 c B, H. p=0.24 H:p <0.24 XD. Ho:p*0.24 H: P = 0.24 OF Hop *0.24 H:p>0.24 What is the test statistic? Z= (Round to two decimal places as needed.)
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6993 subjects randomly selected from an online group involved with ears. There were 1330 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho: p=0.2 H,:p>0.2 O C. Ho: p = 0.2 H:#0.2 O E. Ho: p=0.2 H, p<0.2 OB. Ho:p>0.2 He: p=0.2 OD. Ho: p<0.2 H: p=0.2 OF. Ho: p* 0.2 Hy: p=0.2