Let X1,: faced value of the 1st die; X2: faced value of the 2nd die Y: the sum of two dice. Find: (i) P (X1, <3 n X2 = 5

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answerhappygod
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Let X1,: faced value of the 1st die; X2: faced value of the 2nd die Y: the sum of two dice. Find: (i) P (X1, <3 n X2 = 5

Post by answerhappygod »

Let X1,: faced value of the 1st die;
X2: faced value of the 2nd die
Y: the sum of two dice. Find:
(i) P (X1, <3 n X2 = 5)
(ii) P (X1, = 6 U X2 = 4)
(iii) P (X1, ≤ 5 | Y = 9)
(iv) P (X1 > 4 | X2 ≤ 3)
Let X1 Faced Value Of The 1st Die X2 Faced Value Of The 2nd Die Y The Sum Of Two Dice Find I P X1 3 N X2 5 1
Let X1 Faced Value Of The 1st Die X2 Faced Value Of The 2nd Die Y The Sum Of Two Dice Find I P X1 3 N X2 5 1 (32.88 KiB) Viewed 78 times
(i) P (X<3 n X2 = 5) (ii) P (X = 6 U X2 = 4) (iii) P (X, 55 Y = 9) (iv)P (X, > 4X2 < 3)
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