(a) If 𝜃 is in standard position, then the reference angle 𝜃 is the acute angle formed by the terminal

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answerhappygod
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(a) If 𝜃 is in standard position, then the reference angle 𝜃 is the acute angle formed by the terminal

Post by answerhappygod »

(a) If πœƒ is in standard position, then the reference
angle πœƒ is the acute angle formed by the terminal
side of πœƒ and the (?) . So the reference angle
for πœƒ = 110Β° is πœƒ = (?) Β° , and
that for πœƒ = 210Β° is πœƒ = (?)
Β°.
(b) If πœƒ is any angle, the value of a trigonometric
function of πœƒ is the same, except possibly for sign, as
the value of the trigonometric function
of πœƒ. So sin(110Β°) = sin
(?Β°), and sin(210Β°) = βˆ’sin (?Β°)
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