61. r=1+2 sin Answer (22 + 32 – 2y)2 = 242 + y2 = 45. v 1 = 4, 0 = 10° Answer 4 cos 10°i +4 sin 10° 3.94i + 0.69j

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61. r=1+2 sin Answer (22 + 32 – 2y)2 = 242 + y2 = 45. v 1 = 4, 0 = 10° Answer 4 cos 10°i +4 sin 10° 3.94i + 0.69j

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61 R 1 2 Sin Answer 22 32 2y 2 242 Y2 45 V 1 4 0 10 Answer 4 Cos 10 I 4 Sin 10 3 94i 0 69j 1
61 R 1 2 Sin Answer 22 32 2y 2 242 Y2 45 V 1 4 0 10 Answer 4 Cos 10 I 4 Sin 10 3 94i 0 69j 1 (7.63 KiB) Viewed 25 times
61 R 1 2 Sin Answer 22 32 2y 2 242 Y2 45 V 1 4 0 10 Answer 4 Cos 10 I 4 Sin 10 3 94i 0 69j 2
61 R 1 2 Sin Answer 22 32 2y 2 242 Y2 45 V 1 4 0 10 Answer 4 Cos 10 I 4 Sin 10 3 94i 0 69j 2 (8.15 KiB) Viewed 25 times
#45 Find the horizontal and vertical components of the
vector with given length and direction, and write the vector in
terms of the vectors i and j. Show All work
Thanks!
61. r=1+2 sin Answer (22 + 32 – 2y)2 = 242 + y2 =

45. v 1 = 4, 0 = 10° Answer 4 cos 10°i +4 sin 10° 3.94i + 0.69j
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