-1 A= = 2 2 1 3 -1 -2 -1 2 -

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1 A 2 2 1 3 1 2 1 2 1 (26.67 KiB) Viewed 34 times

Diagonalise the matrix A, that is, find PDP^(−1).
Prove that for a diagonalisable square matrix A, the
determinant is the product of the eigenvalues of A matrix
and the trace is the sum of the eigenvalues of A. You may use
that the trace is cyclic, that is, Tr(ABC) = Tr(CAB) = Tr(BCA), for
any 3 square matrices A, B, C of the same size.
-1 A= = 2 2 1 3 -1 -2 -1 2 -