S(cm) tl (S) t2 () t3 (S) 10 2.81 2.78 2.90 20 4.87 4.84 4.87 30 6.84 6.85 6.81 40 8.47 8.63 8.40 50 10.16 10.12 10.22 s

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answerhappygod
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S(cm) tl (S) t2 () t3 (S) 10 2.81 2.78 2.90 20 4.87 4.84 4.87 30 6.84 6.85 6.81 40 8.47 8.63 8.40 50 10.16 10.12 10.22 s

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S Cm Tl S T2 T3 S 10 2 81 2 78 2 90 20 4 87 4 84 4 87 30 6 84 6 85 6 81 40 8 47 8 63 8 40 50 10 16 10 12 10 22 S 1
S Cm Tl S T2 T3 S 10 2 81 2 78 2 90 20 4 87 4 84 4 87 30 6 84 6 85 6 81 40 8 47 8 63 8 40 50 10 16 10 12 10 22 S 1 (42.1 KiB) Viewed 37 times
S(cm) tl (S) t2 () t3 (S) 10 2.81 2.78 2.90 20 4.87 4.84 4.87 30 6.84 6.85 6.81 40 8.47 8.63 8.40 50 10.16 10.12 10.22 s (m) t(s) Meant(s) $ (m.s-1)
Analysis Plot against t. This should be a straight line with intercept v, and slope a/2. = Explain why this is so. Note that t = 0 must be included in order to obtain the y-intercept, but = = 0 need not be. You must, however, make sure that your y-intercept will lie on the graph. From the graph v, = Slope of the graph = Hence a= Discussion The slope of your graph is , whereas from equation (A2.2) the slope of a v-t graph is a. → Explain the difference. For a block sliding down down a frictionless slope the acceleration is equal to g sin 0, where is the angle that the incline makes with the horizontal, and g is the acceleration due to gravity. Measure the approximate value of @ for the rails, and calculate the value of g sin 0 (Use g = 10 m.s-2) Why is your measured acceleration of the wheel and axle completely different from Why is your measured acceleration of the wheel and axle completely different from g sin ?
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