T B A Fo P Two identical blocks A and B are connected by a lightweight rope. Block A is pulled to the right by a constan

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answerhappygod
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T B A Fo P Two identical blocks A and B are connected by a lightweight rope. Block A is pulled to the right by a constan

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T B A Fo P Two Identical Blocks A And B Are Connected By A Lightweight Rope Block A Is Pulled To The Right By A Constan 1
T B A Fo P Two Identical Blocks A And B Are Connected By A Lightweight Rope Block A Is Pulled To The Right By A Constan 1 (85.66 KiB) Viewed 39 times
my answer is A using the force equations
force equation BEFORE the transition of ONLY A
T B A Fo P Two Identical Blocks A And B Are Connected By A Lightweight Rope Block A Is Pulled To The Right By A Constan 2
T B A Fo P Two Identical Blocks A And B Are Connected By A Lightweight Rope Block A Is Pulled To The Right By A Constan 2 (103.18 KiB) Viewed 39 times
force equation AFTER the transition of ONLY A. A doesn't
experience friction anymore but B still does
T B A Fo P Two Identical Blocks A And B Are Connected By A Lightweight Rope Block A Is Pulled To The Right By A Constan 3
T B A Fo P Two Identical Blocks A And B Are Connected By A Lightweight Rope Block A Is Pulled To The Right By A Constan 3 (99.09 KiB) Viewed 39 times
from this, I think it's A. can you tell me what went wrong using
your own equations and explanation?
T B A Fo P Two identical blocks A and B are connected by a lightweight rope. Block A is pulled to the right by a constant force Fo. The blocks are moving to the right across a rough surface and approach point P, where the rough surface transitions to a surface with negligible friction. How does the tension, T, in the rope connecting the blocks change, if at all, as block A passes point P? T decreases. (B T increases. T remains constant. D The change in T cannot be determined without knowing the coefficient of friction and the mass of the blocks.
pre noi ,{ft,a} {} (580-ft-ma:g. coef=ma: a solve ft-mb.g. coef=mbia -(g. coef. (ma+mb)-to) fomb and ft= ma+mb ma+mb a=
solve (1f0-ft=ma: a {t,a} ft-mb. g. coef=mba (g. coefmb-fo) (g. coef. ma+fo). mb and ft= ma+mb ma+mb
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