1. The ionization energy of lithium is 5.39 eV. Find the effective charge that acts on the outer (2s) electron of the li

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1 The Ionization Energy Of Lithium Is 5 39 Ev Find The Effective Charge That Acts On The Outer 2s Electron Of The Li 1 (32.2 KiB) Viewed 73 times

1. The ionization energy of lithium is 5.39 eV. Find the effective charge that acts on the outer (2s) electron of the lithium atom. met E Energy of the ground state of hydrogen atom is: En 1 32Tºtah? n () 2 If the effective nuclear charge is ze instead of e, then: En 22E n? Here n = 2 for the 2s electron, its ionization energy is E, = 5.39 eV, and E, = 13.6 eV is the ionization energy of the hydrogen atom. Hence: Е, 5,39 eV 2 E 13.6 eV Z=n 1.26 The effective charge is 1.26e and not le which is expected from the perfect shielding by two electrons. The 2s electron has a certain probability of being found inside the 1s electron shell and hence can experience a greater attraction to the nucleus.