5.3 Practice exercise 14.11 Given the standard enthalpy change below, calculate Ach® for Cuo(s): CuO (5) + H2(g) → Cu (s) + H20 (1) AH = - 129.7 kJ using the information provided in Table 4.3 (b) using Hess's Law
TABLE 4.3 Standard Enthalpies of Formation, AfHº at 298 K Substance Formula A Hº (kJ mol-1) Acetylene Ammonia Benzene Calcium carbonate Calcium oxide Carbon dioxide Carbon monoxide Diamond Ethane Ethanol Ethylene Glucose Hydrogen bromide CH2(g) NH3(g) CH.(1) CaCO3(s) CaO(s) CO2(g) CO(g) C(s) CzH(g) C2H5OH(1) C2H2(g) CH 20.(s) HBr(g) 226.8 -46.19 49.0 -1207.1 -635.5 -393.5 --110.5 1.88 ---84.68 -277.7 52.30 --- 1273 --36.23 Substance Formula A Hº (kJ mol-?) Hydrogen chloride Hydrogen fluoride Hydrogen iodide Methane Methanol Propane Silver chloride Sodium bicarbonate Sodium carbonate Sodium chloride Sucrose Water Water vapour HCl(g) HF(8) HI(g) CH,(8) CH,OH(1) C3H (8) AgCl(s) NaHCO3(s) Na2CO3(s) NaCl(s) C12H22011(s) H2O(1) H2O(g) -92.30 268.61 25.9 - 74.80 -238.6 -103.85 127.0 -947.7 - 1130.9 -410.9 -2221 -285.8 -241.8
5.3 Practice exercise 14.11 Given the standard enthalpy change below, calculate Ach® for Cuo(s): CuO (5) + H2(g) → Cu (s
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
5.3 Practice exercise 14.11 Given the standard enthalpy change below, calculate Ach® for Cuo(s): CuO (5) + H2(g) → Cu (s
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!