The standard reduction potentials (E) for the following half reactions are given. Oxaloacetate + 2H+ + 2e → malate E"= -

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answerhappygod
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The standard reduction potentials (E) for the following half reactions are given. Oxaloacetate + 2H+ + 2e → malate E"= -

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The Standard Reduction Potentials E For The Following Half Reactions Are Given Oxaloacetate 2h 2e Malate E 1
The Standard Reduction Potentials E For The Following Half Reactions Are Given Oxaloacetate 2h 2e Malate E 1 (38.92 KiB) Viewed 26 times
The Standard Reduction Potentials E For The Following Half Reactions Are Given Oxaloacetate 2h 2e Malate E 2
The Standard Reduction Potentials E For The Following Half Reactions Are Given Oxaloacetate 2h 2e Malate E 2 (24.82 KiB) Viewed 26 times
The standard reduction potentials (E) for the following half reactions are given. Oxaloacetate + 2H+ + 2e → malate E"= -0.166 V NAD+ + 2H+ + 2e NADH+H E" = -0.320 V If you mixed oxaloacetate, malate, NAD, and NADH together, all at 1M concentrations and in the presence of malate dehydrogenase, which of the following would happen initially? Oxaloacetate and malate would become oxidized; NAD+ and NADH would become reduced Malate would become oxidized, NAD would become reduced.
Oxaloacetate and malate would become oxidized; NAD and NADH would become reduced Malate would become oxidized, NAD would become reduced. O Oxaloacetate would become reduced, NADH would become oxidized. No reaction would occur because all reactants and products are already at their standard concentrations,
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