1.20 mol of each of H2O(g) and Cl20(g) are placed in a 1.00-L flask and allowed to react as H2O(g) + Cl20(g) + 2 HOCI(9)
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
1.20 mol of each of H2O(g) and Cl20(g) are placed in a 1.00-L flask and allowed to react as H2O(g) + Cl20(g) + 2 HOCI(9)
1.20 mol of each of H2O(g) and Cl20(g) are placed in a 1.00-L flask and allowed to react as H2O(g) + Cl20(g) + 2 HOCI(9), with Kc = 0.0900. What will be the concentration of HOCI at equilibrium? = 1.0.313 M 2.0.419 M 3. 0.157 M 4.0.209 M 5.0.0850 M
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!