(iii) Under atmospheric conditions, N20s is effectively in equilibrium with NO2 and NO3: NO, +NO; Kors N₂O, NO k.ods > N
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(iii) Under atmospheric conditions, N20s is effectively in equilibrium with NO2 and NO3: NO, +NO; Kors N₂O, NO k.ods > N
(iii) Under atmospheric conditions, N20s is effectively in equilibrium with NO2 and NO3: NO, +NO; Kors N₂O, NO k.ods > NO, +NO; Where the kobs represents the association reaction and k-obs represents the dissociation reaction Given that the equilibrium constant, K, for the reaction is 3.4x10-11 cm molecule! in the standard state and kobs = 1.0*10-12 cm molecule's calculate the value for k-obs. Are the reactants or product more abundant in the atmosphere? [5 marks]
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