1. Given the ff data: 1.00 mL≎ 1.117 mL HCl, the HCl is 0.4876 N. How much water should be added to 100 mL of the alkali to make it 0.500 N?
2. In standardizing a solution of NaOH against 1.431 grams of KHP, the analyst uses 35.50 ml of the alkali and has to run back with 8.25 ml of acid (1 ml = 10.75 mg NaOH). What is the molarity of NaOH?
3. A solution of H2SO4 is standardized against a sample of which has been previously found to contain 92.44% CaCO3 and no other basic material. The sample weighing 0.7423 g is treated with 42.42 mL of the acid and the excess acid then requires 11.22 mL of NaOH solution. If 1.00 mL of the acid is equivalent to 0.9976 mL of the NaOH, what is the N of each solution?
1. Given the ff data: 1.00 mL≎ 1.117 mL HCl, the HCl is 0.4876 N. How much water should be added to 100 mL of the alkali
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1. Given the ff data: 1.00 mL≎ 1.117 mL HCl, the HCl is 0.4876 N. How much water should be added to 100 mL of the alkali
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