Question c, Can you draw ( make a illustration) to explain how
come these events are seen -4c meters apart and why delta x= 0. If
the event happens 3 seconds apart how come the delta x =0? does
this means because there was no displacement from the lab reference
but there was displacement from the rockect point of view?
(6 AX! - 7 Ax' = - n (ox - Vał) § 10- yc. 3 See) C. - - 40 sec - low =-40 metre © Space time intervals for Lab frame = C²02² - AM² с? c 312 = gc² -0 for Rocked frame - ²0712 - 3x12 25c² - 166² =9c²
Two events occur 3 seconds apart in the same place in the lab system. An observer moves in a rocket relative to the laboratory system at a constant speed, such that the time difference between the events according to the observer is 5 seconds. a. What is the speed of the rocket?Draw the space-time diagrams for both the laboratory system and the rocket. b. According to the observer in the rocket, how far apart are the events spatially? c Show that "space-time intervals" are the same according to the two observers. What do we call such a space-time interval? c-At? – Ax2 = c At'2 – Ax'2 . - . х =
Question c, Can you draw ( make a illustration) to explain how come these events are seen -4c meters apart and why delta
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Question c, Can you draw ( make a illustration) to explain how come these events are seen -4c meters apart and why delta
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